C++ Program to Generate Fibonacci Series with Explanation
C++
Medium
Control Flow
36 views
1 min read
181 words
This problem helps you practice core C++ fundamentals in a practical way. It builds intuition around serie, fibonacci, term. Let’s break it down step by step so you can implement it confidently.
Problem Statement
Print series where each number is sum of previous two: 0,1,1,2,3,5,8...
Real Life: This pattern appears in nature like flower petals, pine cones.
Input Format
An integer n (number of terms).
Output Format
Fibonacci series up to n terms.
Constraints
• n ≥ 1
• Use loop (no recursion)
Concept Explanation
In Fibonacci series, each number is the sum of the previous two numbers.
The series starts with 0 and 1.
Step-by-Step Logic
1.Take input n.
2.Initialize two variables:
• a = 0 (first term)
• b = 1 (second term)
3. Print a and b (if n ≥ 2).
4.For remaining terms:
• next = a + b
• Print next
• Update a = b
• Update b = next
5.Repeat until n terms are printed.
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
void control_q10_fibonacci() {
int terms = 10;
int first = 0, second = 1;
cout << "Fibonacci series: ";
cout << first << " " << second << " ";
for(int i = 3; i <= terms; i++) {
int next = first + second;
cout << next << " ";
first = second;
second = next;
}
cout << endl;
}
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
Print series where each number is sum of previous two: 0,1,1,2,3,5,8...
Real Life: This pattern appears in nature like flower petals, pine cones.
Input / Output
Input
An integer n (number of terms).
Output
Fibonacci series up to n terms.
Constraints
• n ≥ 1
• Use loop (no recursion)
Explanation
Concept Explanation
In Fibonacci series, each number is the sum of the previous two numbers.
The series starts with 0 and 1.
Step-by-Step Explanation
1.Take input n.
2.Initialize two variables:
• a = 0 (first term)
• b = 1 (second term)
3. Print a and b (if n ≥ 2).
4.For remaining terms:
• next = a + b
• Print next
• Update a = b
• Update b = next
5.Repeat until n terms are printed.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
void control_q10_fibonacci() {
int terms = 10;
int first = 0, second = 1;
cout << "Fibonacci series: ";
cout << first << " " << second << " ";
for(int i = 3; i <= terms; i++) {
int next = first + second;
cout << next << " ";
first = second;
second = next;
}
cout << endl;
}
Solutions (0)
No solutions submitted yet. Be the first!
