C++ Program to Convert Decimal to Binary with Explanation
C++
Hard
Control Flow
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1 min read
171 words
This problem helps you practice core C++ fundamentals in a practical way. It builds intuition around decimal, binary, convert. Let’s break it down step by step so you can implement it confidently.
Problem Statement
Convert decimal number to binary (base 2) representation.
Real Life: How computers store all data internally.
Input Format
A positive integer N (decimal number).
Output Format
Binary (base-2) representation of the number.
Constraints
• N ≥ 0
• Use integer arithmetic
Concept Explanation
Computers store all data in binary (0 and 1).
Decimal to binary conversion is done by repeated division by 2.
Step-by-Step Logic
1.Take the decimal number N.
2.If N is 0, binary is 0.
3.While N > 0:
• Find remainder N % 2 (this gives a binary digit).
• Store the remainder.
• Divide N by 2.
4.The remainders are obtained in reverse order.
5.Print the stored remainders from last to first to get binary number.
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
void control_q14_decimal_to_binary() {
int decimal = 25;
int binary[32];
int index = 0;
int temp = decimal;
while(temp > 0) {
binary[index] = temp % 2;
temp = temp / 2;
index++;
}
cout << "Decimal " << decimal << " in binary: ";
for(int i = index - 1; i >= 0; i--) {
cout << binary[i];
}
cout << endl;
}
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
Convert decimal number to binary (base 2) representation.
Real Life: How computers store all data internally.
Input / Output
Input
A positive integer N (decimal number).
Output
Binary (base-2) representation of the number.
Constraints
• N ≥ 0
• Use integer arithmetic
Explanation
Concept Explanation
Computers store all data in binary (0 and 1).
Decimal to binary conversion is done by repeated division by 2.
Step-by-Step Explanation
1.Take the decimal number N.
2.If N is 0, binary is 0.
3.While N > 0:
• Find remainder N % 2 (this gives a binary digit).
• Store the remainder.
• Divide N by 2.
4.The remainders are obtained in reverse order.
5.Print the stored remainders from last to first to get binary number.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
void control_q14_decimal_to_binary() {
int decimal = 25;
int binary[32];
int index = 0;
int temp = decimal;
while(temp > 0) {
binary[index] = temp % 2;
temp = temp / 2;
index++;
}
cout << "Decimal " << decimal << " in binary: ";
for(int i = index - 1; i >= 0; i--) {
cout << binary[i];
}
cout << endl;
}
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