C++ Program to Find Length of String with Explanation
C++
Easy
Strings
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1 min read
168 words
This problem helps you practice core C++ fundamentals in a practical way. It builds intuition around length, total, character. Let’s break it down step by step so you can implement it confidently.
Problem Statement
Count total characters in a string without using library function.
Real Life: Like counting letters in your name.
Input Format
A string S.
Output Format
Total number of characters in the string.
Constraints
• String length ≥ 0
• Do not use any library function like length() or size()
Concept Explanation
We count characters manually by moving through the string
until we reach the null character ''.
This is like counting letters in your name one by one.
Step-by-Step Logic
1.Take input string S.
2.Initialize a counter count = 0.
3.Start from index 0.
4.While current character is not '':
• Increase count by 1.
• Move to next character.
5.When '' is found, stop.
6.Print count.
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
void string_q1_length() {
string text = "Hello World";
int length = 0;
for(int i = 0; text[i] != '�'; i++) {
length++;
}
cout << "String: " << text << endl;
cout << "Length: " << length << endl;
}
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
Count total characters in a string without using library function.
Real Life: Like counting letters in your name.
Input / Output
Output
Total number of characters in the string.
Constraints
• String length ≥ 0
• Do not use any library function like length() or size()
Explanation
Concept Explanation
We count characters manually by moving through the string
until we reach the null character ''.
This is like counting letters in your name one by one.
Step-by-Step Explanation
1.Take input string S.
2.Initialize a counter count = 0.
3.Start from index 0.
4.While current character is not '':
• Increase count by 1.
• Move to next character.
5.When '' is found, stop.
6.Print count.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
void string_q1_length() {
string text = "Hello World";
int length = 0;
for(int i = 0; text[i] != '�'; i++) {
length++;
}
cout << "String: " << text << endl;
cout << "Length: " << length << endl;
}
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