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C++ Program to Deque - Double Ended Queue with Explanation

C++ Hard STL 32 views
This problem helps you practice core C++ fundamentals in a practical way. It builds intuition around add, deque, remove. Let’s break it down step by step so you can implement it confidently.
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Problem Statement

Add/remove from both front and back.
Real Life: Line where you can join from either end.

Input Format

No user input.
Operations are performed on a deque (double-ended queue).

Output Format

Elements of deque after add and remove operations.

Constraints

• Use deque concept

• Add and remove allowed from both ends

Concept Explanation

A deque (double-ended queue) allows insertion and deletion
from both front and back.
This is like a line where people can join or leave from either end.

Step-by-Step Logic

1.Create a deque.

2.Add element at front using push_front().

3.Add element at back using push_back().

4.Remove element from front using pop_front().

5.Remove element from back using pop_back().

6.Print remaining elements of deque.

Code Solution

This explanation is written for learning purposes and to help beginners understand the concept clearly.
void stl_q13_deque() { deque<int> dq; dq.push_back(20); dq.push_back(30); dq.push_front(10); dq.push_front(5); cout << "Deque: "; for(int num : dq) { cout << num << " "; } cout << endl; dq.pop_front(); dq.pop_back(); cout << "After removing from both ends: "; for(int num : dq) { cout << num << " "; } cout << endl; }

Output Example

Input:
Add 10 at front Add 20 at back Add 5 at front Remove from front Remove from back
Output:
Deque elements: 10

Common Mistakes

- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).

Notes & Extra Practice

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