Word Counter
Medium
C
Strings
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Problem Statement
Count how many words are in a sentence. Separate words with a space. Handle multiple spaces. Ignore leading/trailing spaces.
Input Format
A sentence (string) entered by the user.
Output Format
An integer representing total number of words.
Example
" this is a test "
4
Constraints
• Words are separated by spaces
• Multiple spaces may exist
• Leading and trailing spaces must be ignored
• Multiple spaces may exist
• Leading and trailing spaces must be ignored
Concept Explanation
A word is counted when characters appear after a space or at the start, and spaces between words are handled properly.
Step-by-Step Explanation
1.Take the input sentence.
2.Initialize wordCount = 0.
3.Traverse the string character by character.
4.If current character is not a space and:
• it is the first character, or
• the previous character was a space
then a new word starts.
5.Increment wordCount when a new word starts.
6.Continue till the end of the string.
7.Print wordCount
2.Initialize wordCount = 0.
3.Traverse the string character by character.
4.If current character is not a space and:
• it is the first character, or
• the previous character was a space
then a new word starts.
5.Increment wordCount when a new word starts.
6.Continue till the end of the string.
7.Print wordCount
Concept Explanation
A word is counted when characters appear after a space or at the start, and spaces between words are handled properly.
Step-by-Step Explanation
1.Take the input sentence.
2.Initialize wordCount = 0.
3.Traverse the string character by character.
4.If current character is not a space and:
• it is the first character, or
• the previous character was a space
then a new word starts.
5.Increment wordCount when a new word starts.
6.Continue till the end of the string.
7.Print wordCount
2.Initialize wordCount = 0.
3.Traverse the string character by character.
4.If current character is not a space and:
• it is the first character, or
• the previous character was a space
then a new word starts.
5.Increment wordCount when a new word starts.
6.Continue till the end of the string.
7.Print wordCount
Input / Output Format
Input Format
A sentence (string) entered by the user.
Output Format
An integer representing total number of words.
Constraints
• Words are separated by spaces
• Multiple spaces may exist
• Leading and trailing spaces must be ignored
• Multiple spaces may exist
• Leading and trailing spaces must be ignored
Examples
Input:
" this is a test "
Output:
4
Example Solution (Public)
#include <stdio.h>
int main() {
char str[200];
int i;
int count = 0;
printf("Enter a sentence: ");
fgets(str, sizeof(str), stdin);
for (i = 0; str[i] != '�'; i++) {
// Word start condition
if (str[i] != ' ' &&
(i == 0 || str[i - 1] == ' ')) {
count++;
}
}
printf("Number of words = %dn", count);
return 0;
}
Official Solution Code
#include <stdio.h>
int main() {
char str[200];
int i;
int count = 0;
printf("Enter a sentence: ");
fgets(str, sizeof(str), stdin);
for (i = 0; str[i] != '�'; i++) {
// Word start condition
if (str[i] != ' ' &&
(i == 0 || str[i - 1] == ' ')) {
count++;
}
}
printf("Number of words = %dn", count);
return 0;
}
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