Check leap year
Easy
Java
Control Flow
18 views
Problem Statement
Task: return true if year is leap year using correct rules (divisible by 400, or divisible by 4 but not 100).
Input Format
An integer year.
Output Format
true if leap year, otherwise false.
Example
2000
true
Constraints
• year ≥ 1
• Use correct leap year rules
• Use correct leap year rules
Concept Explanation
A year is a leap year if:
• It is divisible by 400, OR
• It is divisible by 4 but not divisible by 100.
• It is divisible by 400, OR
• It is divisible by 4 but not divisible by 100.
Step-by-Step Explanation
1.Read integer year.
2.If year % 400 == 0, return true.
3.Else if year % 4 == 0 and year % 100 != 0, return true.
4.Else return false.
2.If year % 400 == 0, return true.
3.Else if year % 4 == 0 and year % 100 != 0, return true.
4.Else return false.
Concept Explanation
A year is a leap year if:
• It is divisible by 400, OR
• It is divisible by 4 but not divisible by 100.
• It is divisible by 400, OR
• It is divisible by 4 but not divisible by 100.
Step-by-Step Explanation
1.Read integer year.
2.If year % 400 == 0, return true.
3.Else if year % 4 == 0 and year % 100 != 0, return true.
4.Else return false.
2.If year % 400 == 0, return true.
3.Else if year % 4 == 0 and year % 100 != 0, return true.
4.Else return false.
Input / Output Format
Input Format
An integer year.
Output Format
true if leap year, otherwise false.
Constraints
• year ≥ 1
• Use correct leap year rules
• Use correct leap year rules
Examples
Input:
2000
Output:
true
Example Solution (Public)
static boolean isLeap(int y){return (y%400==0)||((y%4==0)&&(y%100!=0));}
Official Solution Code
static boolean isLeap(int y){return (y%400==0)||((y%4==0)&&(y%100!=0));}
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