Java Program to Balance tracker with Explanation
Java
Medium
Variables
23 views
1 min read
180 words
This problem helps you practice core Java fundamentals in a practical way. It builds intuition around balance, negative, transaction. Let’s break it down step by step so you can implement it confidently.
Problem Statement
Task: starting balance and transactions array (+credit, -debit). Return first index where balance becomes negative, else -1.
Input Format
An integer startingBalance
An integer n
Then n integers (transactions: +credit, -debit)
Output Format
Index where balance first becomes negative
If never negative, return -1
Constraints
• n ≥ 0
• Start with balance = 10
Concept Explanation
Start with balance = 10
After index 0 → 10 - 3 = 7
After index 1 → 7 - 4 = 3
After index 2 → 3 - 5 = -2 → negative
So first negative occurs at index 2.
Step-by-Step Logic
1.Read startingBalance, n, and transactions array.
2.Set balance = startingBalance.
3.Loop from i = 0 to n-1:
• Update balance += transactions[i].
• If balance < 0, return i.
4.If loop finishes and balance never negative, return -1.
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
static int firstNegativeBalance(long bal,int[] tx){for(int i=0;i<tx.length;i++){bal+=tx[i];if(bal<0) return i;}return -1;}
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
Task: starting balance and transactions array (+credit, -debit). Return first index where balance becomes negative, else -1.
Input / Output
Input
An integer startingBalance
An integer n
Then n integers (transactions: +credit, -debit)
Output
Index where balance first becomes negative
If never negative, return -1
Constraints
• n ≥ 0
• Start with balance = 10
Explanation
Concept Explanation
Start with balance = 10
After index 0 → 10 - 3 = 7
After index 1 → 7 - 4 = 3
After index 2 → 3 - 5 = -2 → negative
So first negative occurs at index 2.
Step-by-Step Explanation
1.Read startingBalance, n, and transactions array.
2.Set balance = startingBalance.
3.Loop from i = 0 to n-1:
• Update balance += transactions[i].
• If balance < 0, return i.
4.If loop finishes and balance never negative, return -1.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
static int firstNegativeBalance(long bal,int[] tx){for(int i=0;i<tx.length;i++){bal+=tx[i];if(bal<0) return i;}return -1;}
Solutions (0)
No solutions submitted yet. Be the first!