NodeJS Program to Exit Code On Failure with Explanation
NodeJS
Easy
CLI Tools & Debugging
24 views
1 min read
82 words
This problem helps you practice core NodeJS fundamentals in a practical way. It builds intuition around fail, exitcode, exit. Let’s break it down step by step so you can implement it confidently.
Problem Statement
If input string is empty, print FAIL and set exitCode=2.
Input Format
stdin: one line.
Output Format
Print OK/FAIL.
Constraints
Use process.exitCode.
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
const fs = require('fs');
const s = fs.readFileSync(0, 'utf8');
if (!s || !s.trim()) {
console.log('FAIL');
process.exitCode = 2;
} else {
console.log('OK');
}
Output Example
No sample I/O is provided for this question.
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
If input string is empty, print FAIL and set exitCode=2.
Input / Output
Constraints
Use process.exitCode.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
const fs = require('fs');
const s = fs.readFileSync(0, 'utf8');
if (!s || !s.trim()) {
console.log('FAIL');
process.exitCode = 2;
} else {
console.log('OK');
}
Solutions (0)
No solutions submitted yet. Be the first!
