PHP Program to Count Positive Numbers with Explanation
PHP
Easy
PHP Control Flow
30 views
1 min read
90 words
This problem helps you practice core PHP fundamentals in a practical way. It builds intuition around count, positive, get. Let’s break it down step by step so you can implement it confidently.
Problem Statement
You get n and then n integers. Count how many are > 0.
Input Format
First n. Next line n integers.
Output Format
One integer count.
Constraints
n
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
<?php
$inputText=trim(stream_get_contents(STDIN));
if($inputText==='') exit;
$tokens=preg_split('/\\s+/', $inputText);
$i=0; $n=intval($tokens[$i++] ?? 0);
$c=0;
for($k=0;$k<$n;$k++) if(intval($tokens[$i++] ?? 0)>0) $c++;
echo $c;
?>
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
You get n and then n integers. Count how many are > 0.
Input / Output
Input
First n. Next line n integers.
Output
One integer count.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
<?php
$inputText=trim(stream_get_contents(STDIN));
if($inputText==='') exit;
$tokens=preg_split('/\\s+/', $inputText);
$i=0; $n=intval($tokens[$i++] ?? 0);
$c=0;
for($k=0;$k<$n;$k++) if(intval($tokens[$i++] ?? 0)>0) $c++;
echo $c;
?>
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