PHP Program to Count Digits with Explanation
PHP
Medium
PHP Control Flow
28 views
1 min read
81 words
This problem helps you practice core PHP fundamentals in a practical way. It builds intuition around count, digit, one. Let’s break it down step by step so you can implement it confidently.
Problem Statement
Print how many digits are in n (for n=0, answer is 1).
Input Format
One integer n.
Output Format
One integer count.
Constraints
|n|
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
<?php
$inputText=trim(stream_get_contents(STDIN));
if($inputText==='') exit;
$n=intval($inputText);
if($n<0) $n=-$n;
if($n===0){ echo 1; exit; }
$c=0;
while($n>0){ $c++; $n=intdiv($n,10); }
echo $c;
?>
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
Print how many digits are in n (for n=0, answer is 1).
Input / Output
Output
One integer count.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
<?php
$inputText=trim(stream_get_contents(STDIN));
if($inputText==='') exit;
$n=intval($inputText);
if($n<0) $n=-$n;
if($n===0){ echo 1; exit; }
$c=0;
while($n>0){ $c++; $n=intdiv($n,10); }
echo $c;
?>
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