PHP Program to Palindrome Check with Explanation
PHP
Easy
PHP Strings
36 views
1 min read
81 words
This problem helps you practice core PHP fundamentals in a practical way. It builds intuition around palindrome, check, ignoring. Let’s break it down step by step so you can implement it confidently.
Problem Statement
Check if the string is a palindrome ignoring spaces and case.
Input Format
One line string s.
Output Format
YES or NO.
Constraints
|s|
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
<?php
$inputText=rtrim(stream_get_contents(STDIN));
if($inputText==='') exit;
$inputText=strtolower($inputText);
$t='';
for($i=0,$n=strlen($inputText);$i<$n;$i++) if($inputText[$i]!==' ') $t.=$inputText[$i];
$l=0; $r=strlen($t)-1; $ok=true;
while($l<$r){
if($t[$l]!==$t[$r]){ $ok=false; break; }
$l++; $r--;
}
echo $ok ? 'YES' : 'NO';
?>
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
Check if the string is a palindrome ignoring spaces and case.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
<?php
$inputText=rtrim(stream_get_contents(STDIN));
if($inputText==='') exit;
$inputText=strtolower($inputText);
$t='';
for($i=0,$n=strlen($inputText);$i<$n;$i++) if($inputText[$i]!==' ') $t.=$inputText[$i];
$l=0; $r=strlen($t)-1; $ok=true;
while($l<$r){
if($t[$l]!==$t[$r]){ $ok=false; break; }
$l++; $r--;
}
echo $ok ? 'YES' : 'NO';
?>
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