Programming Interview Program to Split Array Largest Sum with Explanation
Programming Interview
Hard
Data Structures
16 views
1 min read
105 words
This problem helps you practice core Programming Interview fundamentals in a practical way. It builds intuition around split, sum, part. Let’s break it down step by step so you can implement it confidently.
Problem Statement
You're given {x}. Split array into m non-empty continuous parts to minimize the maximum part sum. Output that minimum possible value.
Input Format
First line n m. Second line n integers.
Output Format
One integer answer.
Constraints
1
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
import sys
p=sys.stdin.read().strip().split()
if len(p)<2: sys.exit(0)
it=iter(p)
n=int(next(it)); m=int(next(it))
a=[int(next(it)) for _ in range(n)]
lo=max(a)
hi=sum(a)
def can(limit):
parts=1
s=0
for v in a:
if s+v<=limit:
s+=v
else:
parts+=1
s=v
if parts>m:
return False
return True
while lo<hi:
mid=(lo+hi)//2
if can(mid):
hi=mid
else:
lo=mid+1
sys.stdout.write(str(lo))
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
You're given {x}. Split array into m non-empty continuous parts to minimize the maximum part sum. Output that minimum possible value.
Input / Output
Input
First line n m. Second line n integers.
Output
One integer answer.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Difficulty
Hard
Programming Interview
Official Solution
import sys
p=sys.stdin.read().strip().split()
if len(p)<2: sys.exit(0)
it=iter(p)
n=int(next(it)); m=int(next(it))
a=[int(next(it)) for _ in range(n)]
lo=max(a)
hi=sum(a)
def can(limit):
parts=1
s=0
for v in a:
if s+v<=limit:
s+=v
else:
parts+=1
s=v
if parts>m:
return False
return True
while lo<hi:
mid=(lo+hi)//2
if can(mid):
hi=mid
else:
lo=mid+1
sys.stdout.write(str(lo))
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