FizzBuzz Range
Medium
Python
Control Flow
13 views
Problem Statement
Read integer n, for i from 1 to n output on new line: Fizz if i divisible by 3, Buzz if divisible by 5, FizzBuzz if divisible by both, else output i.
Input Format
First line: Integer n
Output Format
• For each number i from 1 to n, print on a new line:
• FizzBuzz if i is divisible by both 3 and 5
• Fizz if i is divisible by 3
• Buzz if i is divisible by 5
• Otherwise print i
• FizzBuzz if i is divisible by both 3 and 5
• Fizz if i is divisible by 3
• Buzz if i is divisible by 5
• Otherwise print i
Example
5
1 2 Fizz 4 Buzz
Constraints
• 1 ≤ n ≤ 10^5
Concept Explanation
For n = 5:
• 1 → not divisible by 3 or 5 → print 1
• 2 → not divisible by 3 or 5 → print 2
• 3 → divisible by 3 → print Fizz
• 4 → not divisible by 3 or 5 → print 4
• 5 → divisible by 5 → print Buzz
• 1 → not divisible by 3 or 5 → print 1
• 2 → not divisible by 3 or 5 → print 2
• 3 → divisible by 3 → print Fizz
• 4 → not divisible by 3 or 5 → print 4
• 5 → divisible by 5 → print Buzz
Step-by-Step Explanation
1.Read integer n.
2.Loop from i = 1 to n:
• If i % 3 == 0 and i % 5 == 0, print "FizzBuzz".
• Else if i % 3 == 0, print "Fizz".
• Else if i % 5 == 0, print "Buzz".
• Otherwise, print i.
2.Loop from i = 1 to n:
• If i % 3 == 0 and i % 5 == 0, print "FizzBuzz".
• Else if i % 3 == 0, print "Fizz".
• Else if i % 5 == 0, print "Buzz".
• Otherwise, print i.
Concept Explanation
For n = 5:
• 1 → not divisible by 3 or 5 → print 1
• 2 → not divisible by 3 or 5 → print 2
• 3 → divisible by 3 → print Fizz
• 4 → not divisible by 3 or 5 → print 4
• 5 → divisible by 5 → print Buzz
• 1 → not divisible by 3 or 5 → print 1
• 2 → not divisible by 3 or 5 → print 2
• 3 → divisible by 3 → print Fizz
• 4 → not divisible by 3 or 5 → print 4
• 5 → divisible by 5 → print Buzz
Step-by-Step Explanation
1.Read integer n.
2.Loop from i = 1 to n:
• If i % 3 == 0 and i % 5 == 0, print "FizzBuzz".
• Else if i % 3 == 0, print "Fizz".
• Else if i % 5 == 0, print "Buzz".
• Otherwise, print i.
2.Loop from i = 1 to n:
• If i % 3 == 0 and i % 5 == 0, print "FizzBuzz".
• Else if i % 3 == 0, print "Fizz".
• Else if i % 5 == 0, print "Buzz".
• Otherwise, print i.
Input / Output Format
Input Format
First line: Integer n
Output Format
• For each number i from 1 to n, print on a new line:
• FizzBuzz if i is divisible by both 3 and 5
• Fizz if i is divisible by 3
• Buzz if i is divisible by 5
• Otherwise print i
• FizzBuzz if i is divisible by both 3 and 5
• Fizz if i is divisible by 3
• Buzz if i is divisible by 5
• Otherwise print i
Constraints
• 1 ≤ n ≤ 10^5
Examples
Input:
5
Output:
1
2
Fizz
4
Buzz
Example Solution (Public)
import sysns=sys.stdin.read().strip()nif not s: sys.exit(0)nn=int(s)nout=[]nfor i in range(1,n+1):n if i%15==0:n out.append('FizzBuzz')n elif i%3==0:n out.append('Fizz')n elif i%5==0:n out.append('Buzz')n else:n out.append(str(i))nsys.stdout.write('
'.join(out))
Official Solution Code
import sysns=sys.stdin.read().strip()nif not s: sys.exit(0)nn=int(s)nout=[]nfor i in range(1,n+1):n if i%15==0:n out.append('FizzBuzz')n elif i%3==0:n out.append('Fizz')n elif i%5==0:n out.append('Buzz')n else:n out.append(str(i))nsys.stdout.write('
'.join(out))
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