Type Aware Reduce
Hard
Python
Data Types
14 views
Problem Statement
Read n values (each is int or float with dot). If all are integers, output PRODUCT as integer. Otherwise output SUM as float with 2 decimals.
Input Format
• First line: Integer n
• Second line: n space-separated values
• Each value is either an integer
• Or a float (contains a dot .)
• Second line: n space-separated values
• Each value is either an integer
• Or a float (contains a dot .)
Output Format
• If all values are integers → print the PRODUCT as an integer
•Otherwise → print the SUM as float with exactly 2 decimal places
•Otherwise → print the SUM as float with exactly 2 decimal places
Example
Sample Input 1 3 2 3 4 Sample Input 2 3 2 3.5 4
Sample Output 1 24 Sample Output 2 9.50
Constraints
• 1 ≤ n ≤ 10^5
• -10^9 ≤ value ≤ 10^9
• Values are valid integers or floats
• -10^9 ≤ value ≤ 10^9
• Values are valid integers or floats
Concept Explanation
Explanation 1
All values are integers.
Product = 2 × 3 × 4 = 24
So output is 24.
Explanation 2
Since one value (3.5) is a float,
we compute SUM instead.
Sum = 2 + 3.5 + 4 = 9.5
Print with 2 decimals → 9.50
All values are integers.
Product = 2 × 3 × 4 = 24
So output is 24.
Explanation 2
Since one value (3.5) is a float,
we compute SUM instead.
Sum = 2 + 3.5 + 4 = 9.5
Print with 2 decimals → 9.50
Step-by-Step Explanation
1.Read integer n.
2.Read list of n values as strings.
3.Check if all values do not contain a dot .:
• If true:
• Convert all to integers.
• Multiply them together.
• Print product.
4.Otherwise:
• Convert all values to float.
• Compute sum.
• Print sum formatted to exactly 2 decimal places.
2.Read list of n values as strings.
3.Check if all values do not contain a dot .:
• If true:
• Convert all to integers.
• Multiply them together.
• Print product.
4.Otherwise:
• Convert all values to float.
• Compute sum.
• Print sum formatted to exactly 2 decimal places.
Concept Explanation
Explanation 1
All values are integers.
Product = 2 × 3 × 4 = 24
So output is 24.
Explanation 2
Since one value (3.5) is a float,
we compute SUM instead.
Sum = 2 + 3.5 + 4 = 9.5
Print with 2 decimals → 9.50
All values are integers.
Product = 2 × 3 × 4 = 24
So output is 24.
Explanation 2
Since one value (3.5) is a float,
we compute SUM instead.
Sum = 2 + 3.5 + 4 = 9.5
Print with 2 decimals → 9.50
Step-by-Step Explanation
1.Read integer n.
2.Read list of n values as strings.
3.Check if all values do not contain a dot .:
• If true:
• Convert all to integers.
• Multiply them together.
• Print product.
4.Otherwise:
• Convert all values to float.
• Compute sum.
• Print sum formatted to exactly 2 decimal places.
2.Read list of n values as strings.
3.Check if all values do not contain a dot .:
• If true:
• Convert all to integers.
• Multiply them together.
• Print product.
4.Otherwise:
• Convert all values to float.
• Compute sum.
• Print sum formatted to exactly 2 decimal places.
Input / Output Format
Input Format
• First line: Integer n
• Second line: n space-separated values
• Each value is either an integer
• Or a float (contains a dot .)
• Second line: n space-separated values
• Each value is either an integer
• Or a float (contains a dot .)
Output Format
• If all values are integers → print the PRODUCT as an integer
•Otherwise → print the SUM as float with exactly 2 decimal places
•Otherwise → print the SUM as float with exactly 2 decimal places
Constraints
• 1 ≤ n ≤ 10^5
• -10^9 ≤ value ≤ 10^9
• Values are valid integers or floats
• -10^9 ≤ value ≤ 10^9
• Values are valid integers or floats
Examples
Input:
Sample Input 1
3
2 3 4
Sample Input 2
3
2 3.5 4
Output:
Sample Output 1
24
Sample Output 2
9.50
Example Solution (Public)
import sysnp=sys.stdin.read().strip().split()nif not p: sys.exit(0)nn=int(p[0])na=p[1:1+n]nall_int=Truenfor s in a:n if '.' in s:n all_int=Falsen breaknif all_int:n prod=1n for s in a:n prod*=int(s)n sys.stdout.write(str(prod))nelse:n sm=0.0n for s in a:n sm+=float(s)n sys.stdout.write(f'{sm:.2f}')
Official Solution Code
import sysnp=sys.stdin.read().strip().split()nif not p: sys.exit(0)nn=int(p[0])na=p[1:1+n]nall_int=Truenfor s in a:n if '.' in s:n all_int=Falsen breaknif all_int:n prod=1n for s in a:n prod*=int(s)n sys.stdout.write(str(prod))nelse:n sm=0.0n for s in a:n sm+=float(s)n sys.stdout.write(f'{sm:.2f}')
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