Vowel Counter
C
Medium
4 views
Problem Description
Count the vowels (a, i, i, o, u) in the string. Case-insensitively. Also keep a separate count of each vowel. You can create a histogram.
Official Solution
#include <stdio.h>
#include <ctype.h>
int main() {
char str[200];
int a = 0, e = 0, i = 0, o = 0, u = 0;
int total = 0;
int idx;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
for (idx = 0; str[idx] != ' '; idx++) {
char ch = tolower(str[idx]);
switch (ch) {
case 'a': a++; total++; break;
case 'e': e++; total++; break;
case 'i': i++; total++; break;
case 'o': o++; total++; break;
case 'u': u++; total++; break;
}
}
printf("nVowel counts:n");
printf("a: %dn", a);
printf("e: %dn", e);
printf("i: %dn", i);
printf("o: %dn", o);
printf("u: %dn", u);
printf("Total vowels: %dn", total);
// Histogram
printf("nHistogram:n");
printf("a | ");
for (idx = 0; idx < a; idx++) printf("*");
printf("n");
printf("e | ");
for (idx = 0; idx < e; idx++) printf("*");
printf("n");
printf("i | ");
for (idx = 0; idx < i; idx++) printf("*");
printf("n");
printf("o | ");
for (idx = 0; idx < o; idx++) printf("*");
printf("n");
printf("u | ");
for (idx = 0; idx < u; idx++) printf("*");
printf("n");
return 0;
}
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