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C++ Program to Check Even/Odd Using Bitwise AND with Explanation

C++ Medium Operators 29 views
This problem helps you practice core C++ fundamentals in a practical way. It builds intuition around odd, even, check. Let’s break it down step by step so you can implement it confidently.
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Problem Statement

Use bitwise AND with 1 to check even/odd instantly.
Real Life: Fastest way to check even/odd in programming.

Input Format

An integer N.

Output Format

Print

• Even
OR

• Odd

Constraints

• Integer value

• Works for positive and negative numbers

Concept Explanation

The least significant bit (LSB) decides even or odd:

• If LSB is 0 → Even

• If LSB is 1 → Odd
Bitwise AND with 1 checks this instantly.

Step-by-Step Logic

1.Take input number N.

2.Apply bitwise AND: N & 1.

3.If result is 0:

• Print Even.

4.Else:

• Print Odd.

Code Solution

This explanation is written for learning purposes and to help beginners understand the concept clearly.
void operator_q9_even_odd_bitwise() { int numbers[] = {12, 15, 18, 21, 24}; for(int i = 0; i < 5; i++) { if(numbers[i] & 1) { cout << numbers[i] << " is Odd" << endl; } else { cout << numbers[i] << " is Even" << endl; } } }

Output Example

Input:
7
Output:
Odd

Common Mistakes

- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).

Notes & Extra Practice

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