PHP Program to Bracket Check Function with Explanation
PHP
Medium
PHP Functions
37 views
1 min read
82 words
This problem helps you practice core PHP fundamentals in a practical way. It builds intuition around function, only, yes. Let’s break it down step by step so you can implement it confidently.
Problem Statement
Write a function balanced(s) for () only. Print YES or NO.
Input Format
One line string s (only '(' and ')').
Output Format
YES or NO.
Constraints
|s|
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
<?php
$inputText=rtrim(stream_get_contents(STDIN));
if($inputText==='') exit;
function balanced($t){
$c=0;
for($i=0,$n=strlen($t);$i<$n;$i++){
if($t[$i]==='(') $c++;
else $c--;
if($c<0) return false;
}
return $c===0;
}
echo balanced($inputText) ? 'YES' : 'NO';
?>
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
Write a function balanced(s) for () only. Print YES or NO.
Input / Output
Input
One line string s (only '(' and ')').
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
<?php
$inputText=rtrim(stream_get_contents(STDIN));
if($inputText==='') exit;
function balanced($t){
$c=0;
for($i=0,$n=strlen($t);$i<$n;$i++){
if($t[$i]==='(') $c++;
else $c--;
if($c<0) return false;
}
return $c===0;
}
echo balanced($inputText) ? 'YES' : 'NO';
?>
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