Jan 27, 2026
## Chapter 10: Recurrence Relations — counting recursion and DP
Here’s the situation.
You write a recursive function.
For n = 10 it runs fast.
For n = 30 it runs okay.
For n = 45 your laptop starts acting like it’s personally offended.
And you think:
“Maybe my code is slow. Maybe Python/Java is slow. Maybe my PC is bad.”
Most times, none of those are the real reason.
The real reason is:
Your function is calling itself too many times.
Recurrence relations are just a clean way to *count* how much work recursion is doing.
### What is a recurrence relation (simple human meaning)
A recurrence is a sentence like:
“Work for size n = work for smaller size + some extra work”
It’s like a progress report:
```text
T(n) = T(smaller) + extra
```
Here:
- T(n) means time (or steps) for input size n
- “smaller” means the size in the recursive call
- “extra” means what you do outside the recursive call
This chapter is not about memorizing formulas.
It’s about reading your own code and predicting growth.
### Why programmers need this
If you want to understand:
- recursion time complexity
- Big-O for divide and conquer
- dynamic programming vs recursion
- why memoization saves you
you need recurrence thinking.
### Three common patterns you’ll see again and again
1) One recursive call:
```text
T(n) = T(n-1) + O(1)
```
2) Two recursive calls (often dangerous):
```text
T(n) = T(n-1) + T(n-2) + O(1)
```
3) Divide and conquer:
```text
T(n) = 2T(n/2) + O(n)
```
Don’t worry if these look strange. We’ll use examples and the shapes will become normal.
#### Basic: sum of first n numbers (one call)
Recursive idea:
```text
sum(n) = sum(n-1) + n
```
Time recurrence:
```text
T(n) = T(n-1) + O(1)
```
Why O(1)? Because outside the recursive call you just do one addition.
Now expand it in your head:
```text
T(n) = T(n-1) + 1
= T(n-2) + 1 + 1
= T(n-3) + 1 + 1 + 1
...
= T(1) + (n-1)
```
So T(n) grows like n.
This is linear time: O(n).
This expansion trick is your best friend.
#### Common mistake: thinking Fibonacci recursion is “just O(n)”
Naive Fibonacci:
```text
fib(n) = fib(n-1) + fib(n-2)
```
Time recurrence:
```text
T(n) = T(n-1) + T(n-2) + O(1)
```
Students often say:
“It’s two calls, so maybe it’s 2n?”
No. It’s not a simple “double”.
It grows like a family tree. Calls keep branching.
Rough intuition:
- fib(45) is not 45 calls
- it’s millions of calls
That’s why it suddenly becomes slow.
Not because your language is slow. Because the call tree exploded.
#### Simple reason: memoization turns a bad recurrence into a good one
Same Fibonacci, but cache results:
- compute fib(k) once
- store it
- reuse it
Then each k from 0..n is computed one time.
So the work becomes closer to:
```text
T(n) = T(n-1) + O(1)
```
which is O(n).
This is the simplest way to understand dynamic programming:
DP is not “magic tables”.
DP is “stop repeating the same subproblem”.
#### Practical: binary search recurrence (why it is O(log n))
Binary search cuts the problem in half each step.
Recurrence:
```text
T(n) = T(n/2) + O(1)
```
Expand the halving:
```text
n → n/2 → n/4 → n/8 → ...
```
How many times can you divide by 2 until you reach 1?
That count is log2(n).
So:
- number of steps ≈ log n
- time complexity = O(log n)
This is why binary search feels “too fast”. It removes half the search space each move.
#### Practical: merge sort recurrence (divide + combine)
Merge sort does:
- split into two halves
- sort each half (recursion)
- merge results (linear work)
So:
```text
T(n) = 2T(n/2) + O(n)
```
Here is a simple recursion-tree intuition (no heavy theorem):
- Level 0: one problem of size n → merge cost n
- Level 1: two problems of size n/2 → total merge cost n
- Level 2: four problems of size n/4 → total merge cost n
Every level costs about n.
How many levels?
Because the size halves each level, you have about log n levels.
So total cost:
```text
n + n + n + ... (log n times) = n log n
```
That’s why merge sort is O(n log n).
This “level counting” is the human-friendly way many engineers use.
#### Extra tip: spotting recurrences in DP (stairs problem)
Classic DP story:
You can climb 1 step or 2 steps.
How many ways to reach step n?
Recurrence for answers:
```text
ways(n) = ways(n-1) + ways(n-2)
```
This looks like Fibonacci, and students panic.
But the trick is: you don’t compute it naively with recursion.
You compute bottom-up:
```text
ways(1), ways(2), ways(3) ... ways(n)
```
Then time becomes O(n) because each state is computed once.
So the same recurrence can lead to:
- exponential time (naive recursion)
- linear time (DP)
Recurrence is the relationship.
Algorithm choice decides the speed.
---
## Conclusion
In this article, we explored the core concepts of All about Computer Mathematics - Recurrence Relations — counting recursion and DP. Understanding these fundamentals is crucial for any developer looking to master this topic.
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