C++ Program to Assignment Operators Problem with Explanation
C++
Easy
Operators
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2 min read
201 words
This problem helps you practice core C++ fundamentals in a practical way. It builds intuition around after, assignment, operator. Let’s break it down step by step so you can implement it confidently.
Problem Statement
Use compound assignment operators (+=, -=, *=, /=, %=).
Real Life: Like updating your bank balance, score etc.
Input Format
Two integers a and b.
Output Format
Values of a after applying compound assignment operators.
Constraints
• Integer values
• b should not be 0 for /= and %=
Concept Explanation
Compound assignment operators update a variable using its current value.
They are shorter and cleaner than writing full expressions.
Used in real life for things like bank balance updates or game scores.
Step-by-Step Logic
1.Start with values a and b.
2.a += b → same as a = a + b.
3.a -= b → same as a = a - b.
4.a *= b → same as a = a * b.
5.a /= b → same as a = a / b.
6.a %= b → same as a = a % b.
7.Print value of a after each operation.
Code Solution
This explanation is written for learning purposes and to help beginners understand the concept clearly.
void operator_q5_assignment() {
int num = 10;
cout << "Initial value: " << num << endl;
num += 5; // num = num + 5
cout << "After += 5: " << num << endl;
num -= 3; // num = num - 3
cout << "After -= 3: " << num << endl;
num *= 2; // num = num * 2
cout << "After *= 2: " << num << endl;
num /= 4; // num = num / 4
cout << "After /= 4: " << num << endl;
}
Output Example
Output:
After += a = 25
After -= a = 15
After *= a = 100
After /= a = 4
After %= a = 0
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Solution Guide
Problem
Use compound assignment operators (+=, -=, *=, /=, %=).
Real Life: Like updating your bank balance, score etc.
Input / Output
Input
Two integers a and b.
Output
Values of a after applying compound assignment operators.
Constraints
• Integer values
• b should not be 0 for /= and %=
Examples
Output:
After += a = 25
After -= a = 15
After *= a = 100
After /= a = 4
After %= a = 0
Explanation
Concept Explanation
Compound assignment operators update a variable using its current value.
They are shorter and cleaner than writing full expressions.
Used in real life for things like bank balance updates or game scores.
Step-by-Step Explanation
1.Start with values a and b.
2.a += b → same as a = a + b.
3.a -= b → same as a = a - b.
4.a *= b → same as a = a * b.
5.a /= b → same as a = a / b.
6.a %= b → same as a = a % b.
7.Print value of a after each operation.
Details
Common Mistakes
- Misreading input/output format.
- Not handling constraints and edge cases.
- Off-by-one errors in loops.
- Forgetting to reset variables between test cases (if any).
Official Solution
void operator_q5_assignment() {
int num = 10;
cout << "Initial value: " << num << endl;
num += 5; // num = num + 5
cout << "After += 5: " << num << endl;
num -= 3; // num = num - 3
cout << "After -= 3: " << num << endl;
num *= 2; // num = num * 2
cout << "After *= 2: " << num << endl;
num /= 4; // num = num / 4
cout << "After /= 4: " << num << endl;
}
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